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pass the text box value from one form to another form textbox jquery

Web Development @ October 19, 2015   Views:0

i need one form textbox value change, In that value pass into another form textbox in my website....


I have tried below code .. its working fine and textbox value should be passing in same form ....but i need one textbox to be one form and another text box to be in another form value should be passed....
{ $("#query2").blur(function(e)
$("#search_head #query").val($(this).val()); }); });

<form id="search_head">

    <input id="query" />
    <input id="query2" placeholder="Blur me" value="Hi there" />

Use .change() .For text boxes, you probaby won't see any difference though.




    <input id="query">

    <input id="query2">

However, if these are on different pages i.e. you need to submit to the server, this won't work. But then you didn't say that.

@diafol thanks for your response ..yeah i need to code for not same page , these two textboxes are diffrent page and how to change textbox1 value should be affected in another form value of textbox2 ??? that only i needed ...

OK, assuming you are submitting the first form normally (submit button->server->operations->response [e.g. serve new page with 2nd form]).
This will have nothing to do with jQuery, unless you want to use webstorage - which I wouldn't suggest for this. It's pure PHP.

You can store the changed data "permanently" in a DB or file or you can store it temporarily in a COOKIE or a session variable. It depends on what the change is supposed to do. If it is part of a 'wizard' or multi-step type form, then you may want to use a session variable. If it is like a change of address, then this would be a permanent change, so use a DB. These are pretty loose rules, since there are many exceptions.


if($_POST && isset($_POST['query']))
    $_SESSION['query_val'] = $_POST['query'];
    $loc = '../secondform.php';
    $loc = '../firstform.php';
header("Location: $loc" );


$qryVal = '';
    $qryVal = $_SESSION['query_val'];

<!-- later on -->
    <input id="query2" value="<?=$qryVal?>" />

Many variations of this type of thing.

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    //The php section of the code


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           $conn = mysqli_connect("localhost", "root", "","rent");

           //echo $sql;

           $result = mysqli_query($conn, $sql)or die(mysqli_error());


           while($row = mysqli_fetch_assoc($result)) {



               return json_encode($arr); ...
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